Mar 05, 2013 · A single mass m1 = 4.1 kg hangs from a spring in a motionless elevator. The spring is extended x = 12 cm from its unstretched length. 1.What is the spring constant of the spring? 2.Now, three masses m1 = 4.1 kg, m2 = 12.3 kg and m3 = 8.2 kg hang from three identical springs in a motionless elevator.
Two blocks of masses `m_1` and `m_2` inter connected by a spring of stiffness `k` are placed on a horizontal surface. If a constant horizontal force F acts on the block `m_1` it slides through a distance x whereas `m_2` remains stationary.
Suspend a helical spring from the clamp with the large end up. Attach a 50 g weight hook with a 50 g slot mass on it to the spring. Record the initial mass of 100 g as m1. The parameter m will represent the total mass on the spring. Place the meter stick vertically alongside the hanging mass. Measure the elongation of the spring and record it ...
1) A system is made of two identical pendula and a massless spring. Each pendulum consists of a massless rigid rod of length b and mass m at end of the rod. The masses are connected by a massless spring of force constant k. The spring is unstretched in the equilibrium position.
P = Pressure (N/m2 or Pa) F = Force applied on a surface (N) A = Area of surface (A) Us = spring potential energy, a.k.a elastic potential energy (J) k = Spring Constant a.k.a. Force constant, or stiffness constant (Mm) Ax = Change in length of spring. I.e. its compression or extension (m) F = Force applied on spring (N)
Two masses m1=1kg and m2 =2kg are connected by suspended by a weightless string by a massless pulley .assume that both the masses start from rest the distance travelled by the centre of mass in 2s is -a) 20/9m b) 40/9m c) 2/3 m d) 1/3 m
A spring of negligible mass and of spring constant 245 N/m is hung vertically and not extended. A mass of 2.5 kg is attached to the spring and it stretches a distance x o. (a) What is x o in meters? Use Hooke’s law (2.5 )(9.8 / )2 245 / 0.10 m o o Fkx mg kg m s x kNm x = == = Now the spring is pulled down an additional distance x = 0.06 meters.